Top ten cheapest cities to retire in america

Top ten cheapest cities to retire in america

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Looking to retire on the cheap? Head to Birmingham, Ala., which a new survey says is the least expensive place to retire in the United States. The survey used cost criteria for groceries,


housing, utilities, transportation and health care to rank America's 150 biggest cities according to affordability. It was conducted by GOBankingRates, a personal finance website.


Birmingham hit the No. 1 spot with its low health care and transportation costs and large inventory of affordable housing. Here are the poll's top 10 least expensive cities, with annual


individual costs across the five categories. 1. Birmingham, Ala.: $33,219 2. Detroit: $33,356 3. Jackson, Miss.: $33,676 4. Memphis, Tenn.: $33,859 5. Toledo, Ohio: $35,095 6. Brownsville,


Texas: $35,461 7. Augusta, Ga.: $35,781 8. Cleveland: $36,056 9. Akron, Ohio: $36,147 10. Montgomery, Ala.: $36,971 Meanwhile, a separate study finds that boomers are optimistic about their


retirement finances. The new survey by Allianz Life shows that 72 percent of boomers are confident that they have enough money saved for retirement. In a similar study in 2010, the company


found only 57 percent of boomers felt good about their retirement savings. Back then half of the boomers surveyed were unsure when they could retire, or if they ever could. According to Paul


Kelash, Allianz Life vice president for consumer insights, the new survey results offer "encouraging news for boomers and prove that with proper focus and engagement, anyone can turn


around a poor savings situation and start building for a successful retirement." Go here to read the full list of the 50 cheapest places to retire.